Ha ha...good ol' permutations eh?!

There really is two ways to solve this question.  

-Let's say you ignore the double 'A'.  Then you could say that there are 2 favorable ways to arrange the word PANDA out of a total of 6! ways to arrange all the letters. This gives you 2/6! which is 1/360 as well.

-I believe the way you taught it is better.  Given that there are repitions it would be best to exclude the repition early.  If you exclude the repition by dividing the total number of arrangements by 2!  (ie. 6!/2!)...then because the repitions are excluded there is only 1 favorable outcome.

this is a tough one too try to explain with text! hope this helps you!!

Steve

The way I see it the numerator could be a 2 if you ignore the fact that there is a double 'A' in pandas...  hence 2/(6!).  if you ignore the double 'A' then you have 2 favorable outcomes out of 6! total outcomes.

A better solution however would be to consider the double 'A' into the calculation and 'divide' it out....that's