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Pg 128 #19 - Nelson Text

 
 
Picture of Terry Hogan
Pg 128 #19 - Nelson Text
by Terry Hogan - Tuesday, 9 October 2012, 10:40 PM
 

Question #19 - How many four-letter arrangements can be made using the letters in the word ALASKA?

I can get the answer in the back (72) by writing out all the ways we can arrange 1 A, 2 As, and 3 As (4, 6, and 4 respectively), and then filling in the blanks using FCP.  I'm sure I'm missing a much easier way using nPr and nCr.  Can someone show me how to do this in less than 15 steps?

Thanks,

Terry Hogan

Picture of Bill Crittenden
Re: Pg 128 #19 - Nelson Text
by Bill Crittenden - Wednesday, 10 October 2012, 7:50 AM
 

case 1: 1A

4! = 24

case 2: 2As

4C2 x 3P2 = 36    (choosing 2 spots to place As) x (picking 2 of the remaining 3 letters)

case 3: 3As

4C3 x 3P1 = 12    (choosing 3 spots to place As) x (picking 1 letter out of 3)

 

24+36+12=72

 

I hope this helps

Picture of Howard Gamble
Re: Pg 128 #19 - Nelson Text
by Howard Gamble - Wednesday, 10 October 2012, 8:17 AM
 

Here is 1 solution

Just considering LSKA   4P4 is 24 ways

considering 3 A's    4 * 3P1 is 12  basically FCP

Considering 2 A's     3C2  any 2 of LSK

                              4P4 /2  for the 2 A's

4P4 + 4*3P1 + 3C2*4P4/2   =  72 ways

Any other ways???

Picture of Candace Ketsa
Re: Pg 128 #19 - Nelson Text
by Candace Ketsa - Thursday, 11 October 2012, 11:01 AM
 

6P4 / 3!

Picture of Terry Hogan
Re: Pg 128 #19 - Nelson Text
by Terry Hogan - Thursday, 18 October 2012, 2:15 PM
 

6P4/3! won't give you the right answer.  That's what my kids jumped to right away. 

Thanks to all responders for the help, we've got it now.